Dream Lake during Moonset?

Hello,

With the full moon just around the corner I was curious if anyone has ever shot Dream Lake during sunrise/moonset? I don't know if the moonset would be visible anywhere near Hallet Peak when shooting lets say near the lake looking west. Does anyone have experience shooting the moonset from Dream Lake?

Thanks,

Derek

In looking at a map of the area, Dream Lake and the Hallett/Flattop massif line up almost east/west, with the line being skewed a few degrees counter-clockwise. Then, taking moon data from the USNO site for next Monday (two days after the full moon), the moon will still be 98% full when the sun rises at 6:30am, and will be 6.5 degrees above the horizon at a compass setting of 261 degrees, which is -- you guessed it -- a little south of west. Whether or not 6.5 degrees is enough for the moon to still be above the mountains, I'm not sure. If not, just go to the next day, when the sun rises at 6:28am, and the moon is nearly 10 degrees above the (imaginary) horizon, at 250 degrees, which is a little farther south of west. And the moon will still have 94% illumination.

Now, if you prefer reflection to frozen lake, fastforward to August 30th. The moon will be 16 degrees above the horizon and 261 degrees on the compass at sunrise.

You now have your assignment. Go forth and calculate!
http://aa.usno.navy.mil/
http://www.topozone.com/map.asp?lat=40.30945&lon=-105.67256&size=l&u=4&datum=nad27&layer=DRG

I think you need least 12 degrees or higher above horizon. If you figure Hallett to be at 12700 feet, dream lake at 9900 feet and the distance between the two about 2.5 miles, you get an angle of about 12 degrees...(but please double check my math).

If you do go, please let us know what it looked like.

Cool,

Thanks Todd! I hadn't even noticed the Altitude/Azimuth lookup table on the USNO sight. I was just getting the times of sunrise/moonsets from this site. It is nice to have the angles as well

After looking at the topozone map of Hallett Peak it does look look a bit south of west when viewed from Dream Lake.

Thanks again,

- Derek

Rene,

Your calculation looks correct based the delta of the heights and distance. I haven't had to use Trig since high school so I needed to refresh the formulas a bit

I see HHooookid on FFF-HHonicks hasn't effected your math skills

Uh Yeah what he said. Actually I was looking at the same figures and thought Tuesday would be best! I'm up for the day Tuesday if I can ride with you!